A=x^2-3x+5

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Solution for A=x^2-3x+5 equation: 



=A^2-3A+5

We move all terms to the left:

-(A^2-3A+5)=0

We get rid of parentheses

-A^2+3A-5=0

We add all the numbers together, and all the variables

-1A^2+3A-5=0

a = -1; b = 3; c = -5;
Δ = b2-4ac
Δ = 32-4·(-1)·(-5)
Δ = -11
Delta is less than zero, so there is no solution for the equation

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